Asked by Yo mama
The data shows the number of miles run per week by randomly selected students from two different classes. Find the difference between the medians. Which class has a higher median? By how much?
Class 1: 6, 8, 10, 11, 14, 4, 5, 8, 2, 7, 7, 5, 10, 12, 11
Class 2: 6, 4, 5, 6, 7, 8, 12, 9, 10, 11, 5, 8, 7, 4, 10
A. Class 2 has a higher median than Class 1 by 0.5 mile.
B. Class 1 has a higher median than Class 2 by 1 mile.
C. Class 1 has a higher median than Class 2 by 0.5 mile.
D. Class 2 has a higher median than Class 1 by 1 mile.
Class 1: 6, 8, 10, 11, 14, 4, 5, 8, 2, 7, 7, 5, 10, 12, 11
Class 2: 6, 4, 5, 6, 7, 8, 12, 9, 10, 11, 5, 8, 7, 4, 10
A. Class 2 has a higher median than Class 1 by 0.5 mile.
B. Class 1 has a higher median than Class 2 by 1 mile.
C. Class 1 has a higher median than Class 2 by 0.5 mile.
D. Class 2 has a higher median than Class 1 by 1 mile.
Answers
Answered by
Bot
To find the median of each class, we need to first order the data sets:
Class 1: 2, 4, 5, 5, 6, 7, 7, 8, 8, 10, 10, 11, 11, 12, 14
Class 2: 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 9, 10, 10, 11, 12
Class 1 has 15 data points, so the median is the middle value, which is 8.
Class 2 also has 15 data points, so the median is the average of the two middle values: (7 + 8) / 2 = 7.5.
Therefore, Class 1 has a higher median than Class 2 by 0.5 mile, which is option C.
Class 1: 2, 4, 5, 5, 6, 7, 7, 8, 8, 10, 10, 11, 11, 12, 14
Class 2: 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 9, 10, 10, 11, 12
Class 1 has 15 data points, so the median is the middle value, which is 8.
Class 2 also has 15 data points, so the median is the average of the two middle values: (7 + 8) / 2 = 7.5.
Therefore, Class 1 has a higher median than Class 2 by 0.5 mile, which is option C.
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