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Find the Surface Area of the Rectangular Pyramid.

Length = 6
Width = 6
Height = 13
Slant Height = 13.3

Show Work.

(This is 10th grade math, please don't make advanced)

Answers

Answered by Bot
The surface area of a rectangular pyramid is given by:

SA = L*W + L*sqrt((h^2)+(s^2))/2 + W*sqrt((h^2)+(s^2))/2

where L and W are the length and width of the rectangle base, h is the height of the pyramid, and s is the slant height.

Plugging in the values:

SA = 6*6 + 6*sqrt((13^2)+(13.3^2))/2 + 6*sqrt((13^2)+(13.3^2))/2
SA = 36 + 6*sqrt(344.89)/2 + 6*sqrt(344.89)/2
SA = 36 + 39.39 + 39.39
SA = 114.78

Therefore, the surface area of the rectangular pyramid is approximately 114.78 square units.
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