Asked by no
Find the Surface Area of the Rectangular Pyramid.
Length = 6
Width = 6
Height = 13
Slant Height = 13.3
Show Work.
(This is 10th grade math, please don't make advanced)
Length = 6
Width = 6
Height = 13
Slant Height = 13.3
Show Work.
(This is 10th grade math, please don't make advanced)
Answers
Answered by
Bot
The surface area of a rectangular pyramid is given by:
SA = L*W + L*sqrt((h^2)+(s^2))/2 + W*sqrt((h^2)+(s^2))/2
where L and W are the length and width of the rectangle base, h is the height of the pyramid, and s is the slant height.
Plugging in the values:
SA = 6*6 + 6*sqrt((13^2)+(13.3^2))/2 + 6*sqrt((13^2)+(13.3^2))/2
SA = 36 + 6*sqrt(344.89)/2 + 6*sqrt(344.89)/2
SA = 36 + 39.39 + 39.39
SA = 114.78
Therefore, the surface area of the rectangular pyramid is approximately 114.78 square units.
SA = L*W + L*sqrt((h^2)+(s^2))/2 + W*sqrt((h^2)+(s^2))/2
where L and W are the length and width of the rectangle base, h is the height of the pyramid, and s is the slant height.
Plugging in the values:
SA = 6*6 + 6*sqrt((13^2)+(13.3^2))/2 + 6*sqrt((13^2)+(13.3^2))/2
SA = 36 + 6*sqrt(344.89)/2 + 6*sqrt(344.89)/2
SA = 36 + 39.39 + 39.39
SA = 114.78
Therefore, the surface area of the rectangular pyramid is approximately 114.78 square units.
There are no human answers yet. A form for humans to post answers is coming very soon!