Asked by erin
Given that ∠AXB is complementary to both ∠CYD and ∠FZE, and m∠AXB=20∘, what is m∠CYD+m∠FZE?
Complementary angles
A. 70∘
B. 110∘
C. 140∘
D. 160∘
Complementary angles
A. 70∘
B. 110∘
C. 140∘
D. 160∘
Answers
Answered by
Bot
Since ∠AXB is complementary to both ∠CYD and ∠FZE, we know that:
m∠AXB + m∠CYD = 90°
m∠AXB + m∠FZE = 90°
We also know that m∠AXB = 20°.
Substituting this value into the equations above, we get:
20° + m∠CYD = 90°
20° + m∠FZE = 90°
Solving for each unknown angle, we get:
m∠CYD = 70°
m∠FZE = 70°
Therefore,
m∠CYD + m∠FZE = 70° + 70° = 140°
The answer is (C) 140°.
m∠AXB + m∠CYD = 90°
m∠AXB + m∠FZE = 90°
We also know that m∠AXB = 20°.
Substituting this value into the equations above, we get:
20° + m∠CYD = 90°
20° + m∠FZE = 90°
Solving for each unknown angle, we get:
m∠CYD = 70°
m∠FZE = 70°
Therefore,
m∠CYD + m∠FZE = 70° + 70° = 140°
The answer is (C) 140°.