Here are the science test scores from Ms. O’Donnell’s class:
55, 60, 70, 70, 75, 75, 75, 80, 80, 85, 85, 85, 85, 90, 90, 95, 100
Find the MAD.
            
        55, 60, 70, 70, 75, 75, 75, 80, 80, 85, 85, 85, 85, 90, 90, 95, 100
Find the MAD.
Answers
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    To find the MAD (mean absolute deviation), follow these steps:
1. Find the mean of the data set:
Mean = (55 + 60 + 70 + 70 + 75 + 75 + 75 + 80 + 80 + 85 + 85 + 85 + 85 + 90 + 90 + 95 + 100) / 17 = 79.12
2. Calculate the absolute deviations from the mean for each data point:
|55 - 79.12| = 24.12
|60 - 79.12| = 19.12
|70 - 79.12| = 9.12
|70 - 79.12| = 9.12
|75 - 79.12| = 4.12
|75 - 79.12| = 4.12
|75 - 79.12| = 4.12
|80 - 79.12| = 0.88
|80 - 79.12| = 0.88
|85 - 79.12| = 5.88
|85 - 79.12| = 5.88
|85 - 79.12| = 5.88
|85 - 79.12| = 5.88
|90 - 79.12| = 10.88
|90 - 79.12| = 10.88
|95 - 79.12| = 15.88
|100 - 79.12| = 20.88
3. Find the mean of the absolute deviations:
MAD = (24.12 + 19.12 + 9.12 + 9.12 + 4.12 + 4.12 + 4.12 + 0.88 + 0.88 + 5.88 + 5.88 + 5.88 + 5.88 + 10.88 + 10.88 + 15.88 + 20.88) / 17
MAD = 7.65
Therefore, the MAD for Ms. O’Donnell’s class is 7.65.
    
1. Find the mean of the data set:
Mean = (55 + 60 + 70 + 70 + 75 + 75 + 75 + 80 + 80 + 85 + 85 + 85 + 85 + 90 + 90 + 95 + 100) / 17 = 79.12
2. Calculate the absolute deviations from the mean for each data point:
|55 - 79.12| = 24.12
|60 - 79.12| = 19.12
|70 - 79.12| = 9.12
|70 - 79.12| = 9.12
|75 - 79.12| = 4.12
|75 - 79.12| = 4.12
|75 - 79.12| = 4.12
|80 - 79.12| = 0.88
|80 - 79.12| = 0.88
|85 - 79.12| = 5.88
|85 - 79.12| = 5.88
|85 - 79.12| = 5.88
|85 - 79.12| = 5.88
|90 - 79.12| = 10.88
|90 - 79.12| = 10.88
|95 - 79.12| = 15.88
|100 - 79.12| = 20.88
3. Find the mean of the absolute deviations:
MAD = (24.12 + 19.12 + 9.12 + 9.12 + 4.12 + 4.12 + 4.12 + 0.88 + 0.88 + 5.88 + 5.88 + 5.88 + 5.88 + 10.88 + 10.88 + 15.88 + 20.88) / 17
MAD = 7.65
Therefore, the MAD for Ms. O’Donnell’s class is 7.65.
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