The expression under the square root sign must be non-negative for real values of x, otherwise the function is undefined. Therefore, we must solve the inequality 6x + 9 ≥ 0.
Subtracting 9 from both sides, we get 6x ≥ -9, and dividing both sides by 6 results in x ≥ -3/2.
Therefore, the domain of the function is x ≥ -3/2, or in interval notation, (-3/2, ∞).
Given the function y = square root of 6x +9 What is the domain of the function?
Hint: Look at the x values when you graph the function in Desmos.
You may use interval notation or inequalities for your answer.
1 answer
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