We can use the formula:
time = distance / speed
The distance in this case is the height of the satellite above the surface of the Earth, which is 3.54 x 10^7 meters.
The speed is the speed of light, which is 3.00 x 10^8 meters per second.
Plugging in these values, we get:
time = 3.54 x 10^7 meters / (3.00 x 10^8 meters per second)
time = 0.118 seconds
Therefore, it would take approximately 0.118 seconds for a radio signal to travel from a satellite orbiting at a height of 3.54 x 10^7 meters to the surface of the Earth.
A radio signal travels at
3
.
00
⋅
10
8
meters per second. How many seconds will it take for a radio signal to travel from a satellite to the surface of Earth if the satellite is orbiting at a height of
3
.
54
⋅
10
7
meters? Show your work.
5 answers
Short awnser please
0.118 seconds.
With an explanation I just want you to explain it shorter
It would take 0.118 seconds for the radio signal to travel from the satellite to the Earth's surface because the satellite is orbiting 3.54 x 10^7 meters above the Earth and radio waves travel at a speed of 3.00 x 10^8 meters per second.