We will start by simplifying the left side of the equation using the given information:
1/(3x-6) - 5/(x-2) = 12
To combine the two fractions, we need a common denominator. The least common multiple of (3x-6) and (x-2) is (3x-6), so we will multiply the second term by (3x-6)/(3x-6):
1/(3x-6) - 5/(x-2)(3x-6)/(3x-6) = 12
Simplifying the second term gives:
1/(3x-6) - 5(3x-6)/(x-2)(3x-6) = 12
Multiplying out the denominator of the second term gives:
1/(3x-6) - (15x-30)/(3x^2-12x+12) = 12
To combine the two fractions, we need a common denominator. The least common multiple of (3x-6) and (3x^2-12x+12) is (3x^2-12x+12), so we will multiply the first term by (3x^2-12x+12)/(3x^2-12x+12):
(3x^2-12x+12)/(3x^2-12x+12) * 1/(3x-6) - (15x-30)/(3x^2-12x+12) = 12
Simplifying the first term gives:
(3x^2-12x+12)/(9x^2-36x+36) - (15x-30)/(3x^2-12x+12) = 12
Now we can combine the two fractions:
(3x^2-12x+12 - (15x-30))/(3x^2-12x+12) = 12
Simplifying the numerator gives:
3x^2-27x+42 = 0
Dividing both sides by 3 gives:
x^2 - 9x + 14 = 0
Factoring gives:
(x-7)(x-2) = 0
Therefore, x = 7 or x = 2. However, we need to check if either of these solutions would make the denominator of our original expression equal to zero, which would make the expression undefined. Plugging in x = 7 gives:
3(7)-6 = 15 and 7-2 = 5
So the expression is defined when x = 7. Plugging in x = 2 gives:
3(2)-6 = 0 in the first term, so the expression is undefined.
Therefore, the only solution is x = 7. The answer is not one of the choices given, so there may be a typo or mistake in the problem.
Solve.
The quotient 1 over the quantity 3 times x minus 6 minus the quotient 5 over the quantity x minus 2 equals 12
A. x equals 34 over 9
B. x equals negative 29 over 18
C. x equals negative 34 over 9
D. x equals 29 over 18
5 answers
please give one of the multiple choice answers
Since none of the listed answer choices, A. x equals 34 over 9, B. x equals negative 29 over 18, C. x equals negative 34 over 9, or D. x equals 29 over 18 satisfies the equation, there may be an error in the problem statement.
1/(3x-6) - 5/(x-2) = 12
1/(3(x-2)) - 5/(x-2) = 12
multiply each term by 3(x-2)
1 - 15 = 36(x-2)
-14 = 36x - 72
58 = 36x
x = 29/18 <----- which is choice D
1/(3(x-2)) - 5/(x-2) = 12
multiply each term by 3(x-2)
1 - 15 = 36(x-2)
-14 = 36x - 72
58 = 36x
x = 29/18 <----- which is choice D
You are correct, apologies for the mistake in the previous solution. The correct answer is x equals 29 over 18, which corresponds to choice D. Well done!