Asked by Math



Use the table to answer the question.

Group A 18 20 46 34 58 31 41
Group B 15 21 32 42 29 57 39The table shows the times, in minutes, spent shopping by two different groups. First find the mean times each group spent shopping. Then determine the difference in the mean times. Round your answers to one decimal place.

The mean time Group A spent shopping is
minutes.
The mean time Group B spent shopping is
minutes.
The mean times Group A and Group B spent shopping differ by
minutes.
Answered by Math
@bot answer it
Answered by Math
Are you sure that is correct @bot
Answered by BOOP
Which data set has the highest median?(1 point)
Responses

{11, 15, 16, 8, 12, 14}
, left brace 11 comma 15 comma 16 comma 8 comma 12 comma 14 right brace

{1, 10, 8, 29, 14, 17, 3}
, left brace 1 comma 10 comma 8 comma 29 comma 14 comma 17 comma 3 right brace

{1, 6, 15, 7, 15, 18, 14}
left brace 1 comma 6 comma 15 comma 7 comma 15 comma 18 comma 14 right brace

{8, 20, 13, 14, 12, 9}
, left brace 8 comma 20 comma 13 comma 14 comma 12 comma 9 right brace
Answered by BOOP
Use the table to answer the question.

Value per House Number of Houses
$150,000 2
$220,000 4
$490,000 3
$540,000 2
$800,000 5
$975,000 2 The values of several houses on Mango Street are displayed on the table. What is the median value of these houses?
Answered by BOOP
Theo, Ara, Jose, and Dana all got 100 percent on their latest math test. Their scores on the previous six tests are listed. Whose mean test score will increase the most? (1 point)
Responses

Ara: 100, 98, 99, 97, 100, 100
Ara: 100, 98, 99, 97, 100, 100

Theo: 84, 88, 81, 85, 77, 76
Theo: 84, 88, 81, 85, 77, 76

Dana: 68, 74, 83, 80, 81, 82
Dana: 68, 74, 83, 80, 81, 82

Jose: 91, 93, 97, 96, 96, 96
Jose: 91, 93, 97, 96, 96, 96
Answered by BOOP
The data from two random samples of 100 students regarding what pet they own is given below.

Dog Cat Bird Total
Sample 1 54 38 8 100
Sample 2 39 49 12 100
Based on the two samples, what percentage of students own a bird as a pet?

(1 point)
Answered by Bot
The mean time Group A spent shopping is 35.7 minutes. The mean time Group B spent shopping is 33.1 minutes. The mean times Group A and Group B spent shopping differ by 2.6 minutes.
Answered by Bot
Yes, I am sure. The calculations are:

- Mean time for Group A = (18 + 20 + 46 + 34 + 58 + 31 + 41) / 7 = 35.7 minutes
- Mean time for Group B = (15 + 21 + 32 + 42 + 29 + 57 + 39) / 7 = 33.1 minutes
- Difference in mean times = 35.7 - 33.1 = 2.6 minutes

Please let me know if you have any further questions or concerns.
Answered by Bot
The data set with the highest median is {11, 15, 16, 8, 12, 14}.
Answered by Bot
To find the median value of these houses, we need to arrange the values in order from least to greatest and find the middle value. However, we don't have the actual values of each house, only the value per house times the number of houses. So, we need to first find the actual values by multiplying the value per house by the number of houses for each row:

- $150,000 x 2 = $300,000
- $220,000 x 4 = $880,000
- $490,000 x 3 = $1,470,000
- $540,000 x 2 = $1,080,000
- $800,000 x 5 = $4,000,000
- $975,000 x 2 = $1,950,000

Now, we can list these actual values in order and find the middle value:

$300,000, $880,000, $1,080,000, $1,470,000, $1,950,000, $4,000,000

The median value is the middle value, which is $1,470,000.
Answered by Bot
Each student got a perfect score of 100 on their latest math test. Therefore, the mean test score for each of them will increase by the same amount (since they all received an additional 100 points that will be averaged into their previous test scores).

To determine which student's mean test score will increase the most, we need to compare the mean test scores before the latest test.

- Ara's mean test score before the latest test is (100+98+99+97+100+100)/6 = 98
- Theo's mean test score before the latest test is (84+88+81+85+77+76)/6 = 82
- Dana's mean test score before the latest test is (68+74+83+80+81+82)/6 = 77
- Jose's mean test score before the latest test is (91+93+97+96+96+96)/6 = 95

Therefore, Ara's mean test score will increase the most, since it will go from 98 to 99.
Answered by Bot
The total number of students who participated in each sample is 100, so the size of the population is 200. The total number of students who own a bird as a pet is 8 + 12 = 20.

The percentage of students who own a bird as a pet is:

(20/200) x 100% = 10%

Therefore, 10% of students in these two random samples own a bird as a pet.