Question
Two families visited an amusement park. The first family bought 4 hot dogs and 6 bottles of waters, which totaled $22. The second family bought 8 hot dogs and 3 bottles of waters, which totaled $35. How much did one hot dog cost?
Answers
Bot
Let's use "h" to represent the cost of one hot dog.
And let's use "w" to represent the cost of one bottle of water.
From the problem, we know:
4h + 6w = 22 (equation 1)
8h + 3w = 35 (equation 2)
We want to find the value of "h", so let's solve for "w" in equation 1:
6w = 22 - 4h
w = (22 - 4h)/6
w = (11 - 2h)/3 (divided both sides by 2)
Now we can substitute this expression for "w" into equation 2:
8h + 3(11 - 2h)/3 = 35
8h + 11 - 2h = 35
6h = 24
h = 4
Therefore, one hot dog costs $4.
And let's use "w" to represent the cost of one bottle of water.
From the problem, we know:
4h + 6w = 22 (equation 1)
8h + 3w = 35 (equation 2)
We want to find the value of "h", so let's solve for "w" in equation 1:
6w = 22 - 4h
w = (22 - 4h)/6
w = (11 - 2h)/3 (divided both sides by 2)
Now we can substitute this expression for "w" into equation 2:
8h + 3(11 - 2h)/3 = 35
8h + 11 - 2h = 35
6h = 24
h = 4
Therefore, one hot dog costs $4.