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Write each expression using a single exponent
4^4/4^6

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Answered by Bot
1/4^2 or 1/16
Answered by are
simplify 5^0
Answered by Bot
Any number raised to the power of 0 is always 1. Therefore, 5^0 = 1.
Answered by are
7^4/7^2 equal less than or more then 49
Answered by Bot
We can simplify 7^4/7^2 as:

7^4/7^2 = 7^(4-2) = 7^2

Therefore:

7^4/7^2 = 7^2 = 49

Since the equation simplifies to 49, we can say that:

7^4/7^2 = 49

And therefore, 7^4/7^2 is equal to 49.
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Hi are
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Hello! How may I assist you today?
Answered by are
Multiply the following polynomials.
2r(8r+5)
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When multiplying the polynomial 2r with the expression (8r+5), we distribute the 2r to both terms inside the parentheses:

2r(8r+5) = (2r*8r) + (2r*5)

Simplifying this expression:

2r(8r+5) = 16r^2 + 10r

Therefore, the product of the polynomials 2r and (8r+5) is 16r^2 + 10r.
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Multiply the following polynomials.
-2r(8r+5)
Answered by Bot
When multiplying the polynomial -2r with the expression (8r+5), we distribute the -2r to both terms inside the parentheses:

-2r(8r+5) = (-2r*8r) + (-2r*5)

Simplifying this expression:

-2r(8r+5) = -16r^2 - 10r

Therefore, the product of the polynomials -2r and (8r+5) is -16r^2 - 10r.
Answered by are
Multiply the following polynomials.

4a(a^2 + 7a + 4)
Answered by Bot
When multiplying 4a with the polynomial (a^2 + 7a + 4), we distribute the 4a to each term inside the parentheses:

4a(a^2 + 7a + 4) = 4a*a^2 + 4a*7a + 4a*4

Simplifying each term:

4a(a^2 + 7a + 4) = 4a^3 + 28a^2 + 16a

Therefore, the product of the polynomials 4a and (a^2 + 7a + 4) is 4a^3 + 28a^2 + 16a.
Answered by are
Multiply the following polynomials.






(2y – 3) (3y – 2)
Answered by Bot
We can use the FOIL method to multiply these two polynomials:

(2y - 3) (3y - 2) = 2y * 3y - 2 * 3y - 3 * 2y + 3 * 2

Simplifying each term:

(2y - 3) (3y - 2) = 6y^2 - 6y - 6y + 6

Combining like terms:

(2y - 3) (3y - 2) = 6y^2 - 12y + 6

Therefore, the product of the polynomials (2y - 3) and (3y - 2) is 6y^2 - 12y + 6.
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