Question
A 50 kg object is moving under the action of a force along a horizontal floor at a constant speed of 4m/s. If the cofficient of sliding friction is 0.5 find the rate of workdone done by the force
Answers
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The rate of work done by the force can be calculated using the formula:
Power = Force x Velocity
However, since the object is moving at a constant speed, the net force acting on it must be zero, meaning that the force applied is equal in magnitude but opposite in direction to the frictional force:
F = frictional force
F = μmg (where μ is the coefficient of sliding friction, m is the mass of the object, and g is the acceleration due to gravity)
F = 0.5 x 50 x 9.81
F = 245.25 N
Therefore, the rate of work done by the force is:
Power = F x v
Power = 245.25 x 4
Power = 981 W or 0.981 kW
So the rate of work done by the force is 0.981 kW.
Power = Force x Velocity
However, since the object is moving at a constant speed, the net force acting on it must be zero, meaning that the force applied is equal in magnitude but opposite in direction to the frictional force:
F = frictional force
F = μmg (where μ is the coefficient of sliding friction, m is the mass of the object, and g is the acceleration due to gravity)
F = 0.5 x 50 x 9.81
F = 245.25 N
Therefore, the rate of work done by the force is:
Power = F x v
Power = 245.25 x 4
Power = 981 W or 0.981 kW
So the rate of work done by the force is 0.981 kW.