We can use the combined gas law formula to solve this problem:
(P1V1/T1) = (P2V2/T2)
Where:
P1 = 93000 kPa (initial pressure)
V1 = 166 cm^3 (initial volume)
T1 = 15°C + 273.15 = 288.15 K (initial temperature in Kelvin)
P2 = 93000 kPa + 7 kPa = 93007 kPa (final pressure)
T2 = 15°C + 5°C + 273.15 = 293.15 K (final temperature in Kelvin)
V2 = ? (final volume)
Substituting the values:
(93000 x 166/288.15) = (93007 x V2/293.15)
Simplifying:
V2 = (93000 x 166 x 293.15) / (288.15 x 93007)
V2 = 169.31 cm^3
Converting to liters:
V2 = 0.16931 L
Therefore, the new volume of the gas at 93007 kPa and 20°C is 0.16931 L.
If the condition on 166cm^3 gas at 93000kpa and 15° are increased by 7kp and 5°c, what will be the new volume of the gas in liter?
1 answer