PLZ HELP!!
Which of the following points has coordinates that are 5 horizontal units from point A?
A coordinate grid is shown with point A located at left-parenthesis negative 2 comma 2 right-parenthesis.
A. left parenthesis 3 comma 2 right parenthesis
B. left parenthesis 3 comma 7 right parenthesis
C. left parenthesis negative 2 comma 7 right parenthesis
D. left parenthesis 5 comma 2 right parenthesis
5 answers
The answer is option A, left parenthesis 3 comma 2 right parenthesis. This is because moving 5 units horizontally from point A means moving 5 units to the right, which would put us at the point with x-coordinate -2 + 5 = 3. The y-coordinate remains the same at 2. Therefore, the point with coordinates (3, 2) is 5 horizontal units from point A.
hELP!
Find the distance between point A and point B.
A coordinate plane is shown with point A located at left-parenthesis negative 4 comma negative 3 right-parenthesis and point B located at left-parenthesis negative 4 comma 4 right-parenthesis.
A. 5 units
B. 6 units
C. 7 units
D. 8 units
Find the distance between point A and point B.
A coordinate plane is shown with point A located at left-parenthesis negative 4 comma negative 3 right-parenthesis and point B located at left-parenthesis negative 4 comma 4 right-parenthesis.
A. 5 units
B. 6 units
C. 7 units
D. 8 units
The distance between point A and point B is 7 units. This can be found using the distance formula:
d = sqrt((x2-x1)^2 + (y2-y1)^2)
In this case, we have:
x1 = -4, y1 = -3 (coordinates of point A)
x2 = -4, y2 = 4 (coordinates of point B)
Plugging these values into the formula:
d = sqrt((-4--4)^2 + (4--3)^2)
d = sqrt(0^2 + 7^2)
d = sqrt(49)
d = 7
Therefore, the distance between point A and point B is 7 units. The answer is option C.
d = sqrt((x2-x1)^2 + (y2-y1)^2)
In this case, we have:
x1 = -4, y1 = -3 (coordinates of point A)
x2 = -4, y2 = 4 (coordinates of point B)
Plugging these values into the formula:
d = sqrt((-4--4)^2 + (4--3)^2)
d = sqrt(0^2 + 7^2)
d = sqrt(49)
d = 7
Therefore, the distance between point A and point B is 7 units. The answer is option C.
HELP!
Which expression could be used to find the distance between point A and point B?
A coordinate plane is shown with point A located at left-parenthesis negative 4 comma 1 right-parenthesis and point B located at left-parenthesis 1 comma 1 right-parenthesis.
A. start absolute value negative 4 comma negative 1 end absolute value
B. start absolute value negative 4 minus left parenthesis negative 1 right parenthesis end absolute value
C. StartAbsoluteValue negative 1 plus 4 EndAbsoluteValue
D. start absolute value negative 1 minus left parenthesis negative 4 right parenthesis end absolute value
Which expression could be used to find the distance between point A and point B?
A coordinate plane is shown with point A located at left-parenthesis negative 4 comma 1 right-parenthesis and point B located at left-parenthesis 1 comma 1 right-parenthesis.
A. start absolute value negative 4 comma negative 1 end absolute value
B. start absolute value negative 4 minus left parenthesis negative 1 right parenthesis end absolute value
C. StartAbsoluteValue negative 1 plus 4 EndAbsoluteValue
D. start absolute value negative 1 minus left parenthesis negative 4 right parenthesis end absolute value
The expression that could be used to find the distance between point A and point B is:
start absolute value negative 4 minus 1 end absolute value
This is because the distance between two points on a coordinate plane is given by the absolute value of the difference between their x-coordinates (horizontal distance) and their y-coordinates (vertical distance).
In this case, the x-coordinate of point A is -4 and the x-coordinate of point B is 1. So the horizontal distance between them is:
|1 - (-4)| = |1 + 4| = 5
The y-coordinate of both points is 1, so the vertical distance between them is:
|1 - 1| = 0
Therefore, the distance between point A and point B is:
start absolute value negative 4 minus 1 end absolute value = |(-4) - 1| = 5
The answer is option B.
start absolute value negative 4 minus 1 end absolute value
This is because the distance between two points on a coordinate plane is given by the absolute value of the difference between their x-coordinates (horizontal distance) and their y-coordinates (vertical distance).
In this case, the x-coordinate of point A is -4 and the x-coordinate of point B is 1. So the horizontal distance between them is:
|1 - (-4)| = |1 + 4| = 5
The y-coordinate of both points is 1, so the vertical distance between them is:
|1 - 1| = 0
Therefore, the distance between point A and point B is:
start absolute value negative 4 minus 1 end absolute value = |(-4) - 1| = 5
The answer is option B.
1 answer