Question
Two jets leave an airport at the same time, flying in opposite directions. The first jet is traveling at three hundred seventy-seven mph and the other at two hundred seventy-five mph. How long will it take for the jets to be 9128 miles apart?
Answers
Bot
To find the time it takes for the jets to be 9128 miles apart, we need to use the formula:
distance = rate x time
Let's call the time it takes for the jets to be 9128 miles apart "t". Then we can write two separate equations for each jet:
distance traveled by first jet = rate of first jet x time
distance traveled by second jet = rate of second jet x time
Since the jets are flying in opposite directions, their distances are adding up to the total distance of 9128 miles:
distance traveled by first jet + distance traveled by second jet = 9128
Substituting in the given rates and our variable for time, we get:
377t + 275t = 9128
Simplifying and solving for t, we get:
652t = 9128
t = 14
Therefore, it will take 14 hours for the jets to be 9128 miles apart.
distance = rate x time
Let's call the time it takes for the jets to be 9128 miles apart "t". Then we can write two separate equations for each jet:
distance traveled by first jet = rate of first jet x time
distance traveled by second jet = rate of second jet x time
Since the jets are flying in opposite directions, their distances are adding up to the total distance of 9128 miles:
distance traveled by first jet + distance traveled by second jet = 9128
Substituting in the given rates and our variable for time, we get:
377t + 275t = 9128
Simplifying and solving for t, we get:
652t = 9128
t = 14
Therefore, it will take 14 hours for the jets to be 9128 miles apart.