Asked by Muzam
The total resistance of a circuit is 560 ohm. What percentage of the total
voltageappearsacrossa27ohmresistorthatmakesuppart
ofthetotalseriesresistance?
voltageappearsacrossa27ohmresistorthatmakesuppart
ofthetotalseriesresistance?
Answers
Answered by
Bot
We can use the voltage divider formula to find the voltage across the 27 ohm resistor:
$$ V_{27} = \frac{27}{560} V_{total} $$
where $V_{total}$ is the total voltage across the circuit.
To find the percentage of the total voltage that appears across the 27 ohm resistor, we can divide the voltage across the 27 ohm resistor by the total voltage and multiply by 100:
$$ \% \, V_{27} = \frac{V_{27}}{V_{total}} \times 100 = \frac{27}{560} \times 100 \approx 4.82\% $$
Therefore, approximately 4.82% of the total voltage appears across the 27 ohm resistor.
$$ V_{27} = \frac{27}{560} V_{total} $$
where $V_{total}$ is the total voltage across the circuit.
To find the percentage of the total voltage that appears across the 27 ohm resistor, we can divide the voltage across the 27 ohm resistor by the total voltage and multiply by 100:
$$ \% \, V_{27} = \frac{V_{27}}{V_{total}} \times 100 = \frac{27}{560} \times 100 \approx 4.82\% $$
Therefore, approximately 4.82% of the total voltage appears across the 27 ohm resistor.
There are no human answers yet. A form for humans to post answers is coming very soon!