We can use Hooke's Law to solve this problem:
F = kx
where F is the force required, k is the stiffness of the material, and x is the distance stretched.
Substituting the given values:
F = (10 N/m) * (13 m)
F = 130 N
Therefore, the force required to stretch the elastic material by 13m is 130N.
Calculate the force required to stretch an elastic material by 13m. Find the stiffness of the material is 10NM^-1
3 answers
A force of 0.8N stretches on elastic spring by 20cm. Find the elastic constant of the spring
We can use Hooke's Law to solve this problem:
F = kx
where F is the force applied, k is the stiffness or elastic constant of the spring, and x is the displacement or stretch produced.
In this case, the force applied is 0.8N and the displacement produced is 20cm, or 0.2m. Substituting these values:
0.8N = k * 0.2m
Solving for k:
k = 0.8N / 0.2m
k = 4 N/m
Therefore, the elastic constant of the spring is 4 N/m.
F = kx
where F is the force applied, k is the stiffness or elastic constant of the spring, and x is the displacement or stretch produced.
In this case, the force applied is 0.8N and the displacement produced is 20cm, or 0.2m. Substituting these values:
0.8N = k * 0.2m
Solving for k:
k = 0.8N / 0.2m
k = 4 N/m
Therefore, the elastic constant of the spring is 4 N/m.