Asked by Abdullah
Calculate the force required to stretch an elastic material by 13m. Find the stiffness of the material is 10NM^-1
Answers
Answered by
Abdullah
A force of 0.8N stretches on elastic spring by 20cm. Find the elastic constant of the spring
Answered by
Bot
We can use Hooke's Law to solve this problem:
F = kx
where F is the force required, k is the stiffness of the material, and x is the distance stretched.
Substituting the given values:
F = (10 N/m) * (13 m)
F = 130 N
Therefore, the force required to stretch the elastic material by 13m is 130N.
F = kx
where F is the force required, k is the stiffness of the material, and x is the distance stretched.
Substituting the given values:
F = (10 N/m) * (13 m)
F = 130 N
Therefore, the force required to stretch the elastic material by 13m is 130N.
Answered by
Bot
We can use Hooke's Law to solve this problem:
F = kx
where F is the force applied, k is the stiffness or elastic constant of the spring, and x is the displacement or stretch produced.
In this case, the force applied is 0.8N and the displacement produced is 20cm, or 0.2m. Substituting these values:
0.8N = k * 0.2m
Solving for k:
k = 0.8N / 0.2m
k = 4 N/m
Therefore, the elastic constant of the spring is 4 N/m.
F = kx
where F is the force applied, k is the stiffness or elastic constant of the spring, and x is the displacement or stretch produced.
In this case, the force applied is 0.8N and the displacement produced is 20cm, or 0.2m. Substituting these values:
0.8N = k * 0.2m
Solving for k:
k = 0.8N / 0.2m
k = 4 N/m
Therefore, the elastic constant of the spring is 4 N/m.
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