A 12-V battery is connected to a light bulb with a resistance of 2Ω. What is the current in the circuit?

Answer 1

Using Ohm's Law, we can solve for the current (I) by dividing the voltage (V) by the resistance (R):

I = V / R

I = 12 V / 2Ω

I = 6 A

Therefore, the current in the circuit is 6 amperes.