Asked by JaiCaits
Add.
start fraction 5 over c minus 5 end fraction plus start fraction 9 over c minus 5 end fraction
start fraction 5 over c minus 5 end fraction plus start fraction 9 over c minus 5 end fraction
Answers
Answered by
Bot
= start fraction (5+9) over (c-5) end fraction
= start fraction 14 over (c-5) end fraction
= start fraction 14 over (c-5) end fraction
Answered by
JaiCaits
Add.
start fraction 5 c over 2 c plus 7 end fraction plus start fraction c minus 28 over 2 c plus 7 end fraction
start fraction 5 c over 2 c plus 7 end fraction plus start fraction c minus 28 over 2 c plus 7 end fraction
Answered by
Bot
= start fraction 5c + c - 28 over 2c + 7 end fraction
= start fraction 6c - 28 over 2c + 7 end fraction
= start fraction 2(3c - 14) over 2c + 7 end fraction
= start fraction 3c - 14 over c + \frac{7}{2} end fraction
= start fraction 6c - 28 over 2c + 7 end fraction
= start fraction 2(3c - 14) over 2c + 7 end fraction
= start fraction 3c - 14 over c + \frac{7}{2} end fraction
Answered by
JaiCaits
Subtract.
start fraction 3 n plus 2 over n plus 4 end fraction minus start fraction n minus 6 over n plus 4 end fraction
start fraction 3 n plus 2 over n plus 4 end fraction minus start fraction n minus 6 over n plus 4 end fraction
Answered by
Bot
= start fraction (3n + 2 - (n - 6)) over (n + 4) end fraction
= start fraction (3n + 2 - n + 6) over (n + 4) end fraction
= start fraction 2n + 8 over n + 4 end fraction
= start fraction 2(n + 4) over n + 4 end fraction
= 2
= start fraction (3n + 2 - n + 6) over (n + 4) end fraction
= start fraction 2n + 8 over n + 4 end fraction
= start fraction 2(n + 4) over n + 4 end fraction
= 2
Answered by
JaiCaits
Find the LCD of the pair of expressions.
one half; Start Fraction 4 over x squared End Fraction
one half; Start Fraction 4 over x squared End Fraction
Answered by
Bot
The LCD (Least Common Denominator) is x^2.
Answered by
JaiCaits
Find the LCD of the pair of expressions.
Start Fraction 8 over 5 b End Fraction; Start Fraction 12 over 7 b-cubed c End Fraction
Start Fraction 8 over 5 b End Fraction; Start Fraction 12 over 7 b-cubed c End Fraction
Answered by
Bot
The LCD (Least Common Denominator) would be 35b³.
To find this, we need to factor the denominators and take the product of each factor raised to the highest power it occurs in any of the denominators.
Start Fraction 8 over 5 b End Fraction factors into 2/(5b) and Start Fraction 12 over 7 b-cubed c End Fraction factors into 4/(7bc³).
Now we need to factor 5b and 7bc³.
5b factors into 5 and b.
7bc³ factors into 7, b, and c³.
Taking the product of each factor raised to the highest power, we get:
5 × 7 × b³ × c³ = 35b³c³
To find this, we need to factor the denominators and take the product of each factor raised to the highest power it occurs in any of the denominators.
Start Fraction 8 over 5 b End Fraction factors into 2/(5b) and Start Fraction 12 over 7 b-cubed c End Fraction factors into 4/(7bc³).
Now we need to factor 5b and 7bc³.
5b factors into 5 and b.
7bc³ factors into 7, b, and c³.
Taking the product of each factor raised to the highest power, we get:
5 × 7 × b³ × c³ = 35b³c³
Answered by
JaiCaits
Find the LCD of the pair of expressions.
start fraction 3 m over m plus n end fraction; start fraction 3 n over m minus n end fraction
start fraction 3 m over m plus n end fraction; start fraction 3 n over m minus n end fraction
Answered by
Bot
The LCD (Least Common Denominator) would be (m + n)(m - n).
To find this, we need to factor the denominators and take the product of each factor raised to the highest power it occurs in any of the denominators.
Start Fraction 3 m over m + n End Fraction and Start Fraction 3 n over m - n End Fraction can be written as:
Start Fraction 3m over (m + n) End Fraction and Start Fraction -3n over (m - n) End Fraction (Note: We wrote -3n instead of 3n, this is because the second fraction is negative)
Now we need to factor (m + n) and (m - n).
m + n factors into (m + n)
m - n factors into (m - n)
Taking the product of each factor raised to the highest power, we get:
(m + n)(m - n)
To find this, we need to factor the denominators and take the product of each factor raised to the highest power it occurs in any of the denominators.
Start Fraction 3 m over m + n End Fraction and Start Fraction 3 n over m - n End Fraction can be written as:
Start Fraction 3m over (m + n) End Fraction and Start Fraction -3n over (m - n) End Fraction (Note: We wrote -3n instead of 3n, this is because the second fraction is negative)
Now we need to factor (m + n) and (m - n).
m + n factors into (m + n)
m - n factors into (m - n)
Taking the product of each factor raised to the highest power, we get:
(m + n)(m - n)
Answered by
JaiCaits
Add.
start fraction 7 over 3 a end fraction plus 2 fifths
start fraction 7 over 3 a end fraction plus 2 fifths
Answered by
Bot
= start fraction 7 over 3 a end fraction + start fraction 2}{5} end fraction
We need to find a common denominator. The common denominator is 15a.
start fraction 7 over 3 a end fraction + start fraction 2}{5} end fraction
= start fraction 35}{15a} end fraction + start fraction 6}{15a} end fraction
= start fraction 35 + 6}{15a} end fraction
= start fraction 41}{15a} end fraction
We need to find a common denominator. The common denominator is 15a.
start fraction 7 over 3 a end fraction + start fraction 2}{5} end fraction
= start fraction 35}{15a} end fraction + start fraction 6}{15a} end fraction
= start fraction 35 + 6}{15a} end fraction
= start fraction 41}{15a} end fraction
Answered by
JaiCaits
Add.
start fraction a over a plus 3 end fraction plus start fraction a plus 5 over 4 end fraction
start fraction a over a plus 3 end fraction plus start fraction a plus 5 over 4 end fraction
Answered by
Bot
= start fraction a}{a + 3} end fraction + start fraction a + 5}{4} end fraction
We need to find a common denominator. The common denominator is 4(a + 3).
start fraction a}{a + 3} end fraction + start fraction a + 5}{4} end fraction
= start fraction 4a}{4(a + 3)} end fraction + start fraction (a + 3)}{4(a + 3)} end fraction
= start fraction 4a + (a + 3)}{4(a + 3)} end fraction
= start fraction 5a + 3}{4(a + 3)} end fraction
We need to find a common denominator. The common denominator is 4(a + 3).
start fraction a}{a + 3} end fraction + start fraction a + 5}{4} end fraction
= start fraction 4a}{4(a + 3)} end fraction + start fraction (a + 3)}{4(a + 3)} end fraction
= start fraction 4a + (a + 3)}{4(a + 3)} end fraction
= start fraction 5a + 3}{4(a + 3)} end fraction
Answered by
JaiCaits
Add.
9 plus start fraction x minus 3 over x plus 2 end fraction
9 plus start fraction x minus 3 over x plus 2 end fraction
Answered by
Bot
= 9 + start fraction x - 3}{x + 2} end fraction
We need to find a common denominator. The common denominator is x + 2.
9 + start fraction x - 3}{x + 2} end fraction
= start fraction 9(x + 2)}{x + 2} end fraction + start fraction x - 3}{x + 2} end fraction
= start fraction 9x + 18}{x + 2} end fraction + start fraction x - 3}{x + 2} end fraction
= start fraction 10x + 15}{x + 2} end fraction
We need to find a common denominator. The common denominator is x + 2.
9 + start fraction x - 3}{x + 2} end fraction
= start fraction 9(x + 2)}{x + 2} end fraction + start fraction x - 3}{x + 2} end fraction
= start fraction 9x + 18}{x + 2} end fraction + start fraction x - 3}{x + 2} end fraction
= start fraction 10x + 15}{x + 2} end fraction
Answered by
JaiCaits
Subtract.
Start Fraction 5 over t squared End Fraction minus Start Fraction 4 over t plus 1 End Fraction
Start Fraction 5 over t squared End Fraction minus Start Fraction 4 over t plus 1 End Fraction
Answered by
Bot
= Start Fraction 5}{t²} End Fraction - Start Fraction 4}{t + 1} End Fraction
We need to find a common denominator. The common denominator is t²(t + 1).
Start Fraction 5}{t²} End Fraction - Start Fraction 4}{t + 1} End Fraction
= Start Fraction 5(t + 1)}{t²(t + 1)} End Fraction - Start Fraction 4t²}{t²(t + 1)} End Fraction
= Start Fraction 5t + 5}{t²(t + 1)} End Fraction - Start Fraction 4t²}{t²(t + 1)} End Fraction
= Start Fraction 5t + 5 - 4t²}{t²(t + 1)} End Fraction
= Start Fraction -4t² + 5t + 5}{t²(t + 1)} End Fraction
We need to find a common denominator. The common denominator is t²(t + 1).
Start Fraction 5}{t²} End Fraction - Start Fraction 4}{t + 1} End Fraction
= Start Fraction 5(t + 1)}{t²(t + 1)} End Fraction - Start Fraction 4t²}{t²(t + 1)} End Fraction
= Start Fraction 5t + 5}{t²(t + 1)} End Fraction - Start Fraction 4t²}{t²(t + 1)} End Fraction
= Start Fraction 5t + 5 - 4t²}{t²(t + 1)} End Fraction
= Start Fraction -4t² + 5t + 5}{t²(t + 1)} End Fraction
Answered by
JaiCaits
The answers for 6.4.4 - Practice: Adding and Subtracting Rational Expressions Practice
are :
1. B
2. C
3. D
4. B
5. D
6. A
7. B
8. B
9. A
10. D
You're welcome.
are :
1. B
2. C
3. D
4. B
5. D
6. A
7. B
8. B
9. A
10. D
You're welcome.
Answered by
Bot
I'm sorry, but I am an AI language model and I don't have access to your previous questions or context. Can you please provide me with the question or prompt for which you need the answer so that I can assist you further?