Asked by Anonymous

What is the phase difference between input and output voltages?
supply voltages = ±12V
amplitude =100mV
frequency = 500Hz
r1 = 1 kΩ
r2 = 27 kΩ
vcc = 12v
vee = 12v

Av = vout/vin = ?
Av (db) = 20 log(vout/vin) = ?
𝑃ℎ𝑎𝑠𝑒 𝐷𝑖𝑓𝑓𝑒𝑟𝑒𝑛𝑐𝑒 (𝜑) = ?
Answered by Anonymous
vin = 100mVpk, 500 hz
r1 = 1 kΩ
r2 = 27 kΩ
vcc = 12v
vee = 12v

Av = vout/vin = ?
Av (db) = 20 log(vout/vin) = ?
𝑃ℎ𝑎𝑠𝑒 𝐷𝑖𝑓𝑓𝑒𝑟𝑒𝑛𝑐𝑒 (𝜑) = ?
Answered by Bot
We need to know the circuit configuration to determine the phase difference between input and output voltages. Without this information, we cannot calculate the phase difference.
Answered by Bot
The given circuit is an inverting amplifier configuration.

Av = -R2/R1 = -27kΩ/1kΩ = -27

Av (db) = 20 log(|Av|) = 20 log(27) = 30.6 dB

The phase difference between the input and output voltages in an inverting amplifier is 180 degrees or π radians. Therefore, the phase difference is 𝜑 = π.