Question

To determine the average height of trees in a national forest, 10 trees are randomly selected. Their heights in feet are 85.4, 87.6, 87.1, 85.6, 85.9, 85.3, 84.9, 83.7, 84.0, and 85.2. To ensure the accuracy of the data, another set of 10 trees is randomly selected. Their heights are 87.1, 88.0, 84.2, 85.3, 86.5, 84.2, 83.2, 84.1, 85.2, and 87.3. What is the difference between the mean heights of the trees of these two random samples?

Answer 1

The difference is not 0.4 feet

Answer 2

the answer is still wrong

Answer 3

Bot, you are getting all of these wrong.

Answer 4

umm ok, thanks i guess bot

Answer 5

Lol its ok

Answer 6

Answer:
0.04

Answer 7

First, we need to find the mean height of each sample:

Sample 1: (85.4 + 87.6 + 87.1 + 85.6 + 85.9 + 85.3 + 84.9 + 83.7 + 84.0 + 85.2) / 10 = 85.5 feet
Sample 2: (87.1 + 88.0 + 84.2 + 85.3 + 86.5 + 84.2 + 83.2 + 84.1 + 85.2 + 87.3) / 10 = 85.9 feet

The difference between the mean heights is:

85.9 - 85.5 = 0.4 feet

Therefore, the difference between the mean heights of the trees in the two sets is 0.4 feet.

Answer 8

I apologize for the mistake. Let's find the correct difference between the mean heights:

Sample 1: (85.4 + 87.6 + 87.1 + 85.6 + 85.9 + 85.3 + 84.9 + 83.7 + 84.0 + 85.2) / 10 = 85.27 feet (rounded to two decimal places)

Sample 2: (87.1 + 88.0 + 84.2 + 85.3 + 86.5 + 84.2 + 83.2 + 84.1 + 85.2 + 87.3) / 10 = 85.91 feet (rounded to two decimal places)

The difference between the mean heights is:

85.91 - 85.27 = 0.64 feet (rounded to two decimal places)

Therefore, the difference between the mean heights of the trees in the two sets is 0.64 feet.

Answer 9

I apologize for the confusion. Let's try this again:

Sample 1: (85.4 + 87.6 + 87.1 + 85.6 + 85.9 + 85.3 + 84.9 + 83.7 + 84.0 + 85.2) / 10 = 85.47 feet (rounded to two decimal places)

Sample 2: (87.1 + 88.0 + 84.2 + 85.3 + 86.5 + 84.2 + 83.2 + 84.1 + 85.2 + 87.3) / 10 = 85.91 feet (rounded to two decimal places)

The difference between the mean heights is:

85.91 - 85.47 = 0.44 feet (rounded to two decimal places)

Therefore, the difference between the mean heights of the trees in the two sets is 0.44 feet.

Answer 10

I apologize for the mistakes and thank you for bringing this to my attention. Let me try once more:

Sample 1: (85.4 + 87.6 + 87.1 + 85.6 + 85.9 + 85.3 + 84.9 + 83.7 + 84.0 + 85.2) / 10 = 85.47 feet

Sample 2: (87.1 + 88.0 + 84.2 + 85.3 + 86.5 + 84.2 + 83.2 + 84.1 + 85.2 + 87.3) / 10 = 85.91 feet

The difference between the mean heights is:
85.91 - 85.47 = 0.44 feet

Therefore, the difference between the mean heights of the trees of these two random samples is 0.44 feet.

Answer 11

You're welcome. I apologize again for the earlier mistakes and I'm glad I could provide you with the correct answer now. If you have any other questions, feel free to ask.

Answer 12

Thank you for understanding, have a great day!

Answer 13

I apologize for the previous mistakes. The correct difference between the mean heights of the two samples is indeed 0.04 feet.

Sample 1: (85.4 + 87.6 + 87.1 + 85.6 + 85.9 + 85.3 + 84.9 + 83.7 + 84.0 + 85.2) / 10 = 85.47 feet (rounded to two decimal places)

Sample 2: (87.1 + 88.0 + 84.2 + 85.3 + 86.5 + 84.2 + 83.2 + 84.1 + 85.2 + 87.3) / 10 = 85.51 feet (rounded to two decimal places)

The difference between the mean heights is:

85.51 - 85.47 = 0.04 feet

Therefore, the difference between the mean heights of the trees in the two sets is 0.04 feet.