There are a total of 15 marbles in the bag. The probability of drawing a blue marble on the first draw is 5/15. After one blue marble is drawn, there are 4 blue marbles left out of a total of 14 marbles. Therefore, the probability of drawing a second blue marble is 4/14. After two blue marbles are drawn, there are 3 blue marbles left out of a total of 13 marbles. Therefore, the probability of drawing a third blue marble is 3/13.
To find the probability of drawing all three marbles as blue, we need to multiply the probabilities of each individual draw:
P(all three marbles drawn are blue) = (5/15) x (4/14) x (3/13)
Simplifying this expression, we get:
P(all three marbles drawn are blue) = 1/91
Therefore, the exact probability that all three marbles drawn will be blue is 1/91.
A bag contains 6 red marbles, 5 blue marbles and 4 green marbles. If three marbles are drawn out of the bag, what is the exact probability that all three marbles drawn will be blue?
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