Question

Two force of magnitude of 25N and 16 N are inclined at an angle of 120°to each other.calculate the magnitude of their resultant.

Answer 1

AAAaannndd the bot gets it wrong yet again!
Sorry - you have calculated the wrong diagonal. You want
r^2 = 25^2 + 16^2 - 2(25)(16)cos(60°)
r = √481 ≈ 21.93

Answer 2

Using the law of cosines, we can calculate the magnitude of the resultant force:

R^2 = 25^2 + 16^2 - 2(25)(16)cos(120)

R^2 = 625 + 256 - 800(-0.5)

R^2 = 625 + 256 + 400

R^2 = 1281

R = √1281

R ≈ 35.78 N

Therefore, the magnitude of the resultant force is approximately 35.78 N.

Answer 3

I apologize for the mistake in my previous answer. You are correct that the angle between the forces is 60° and not 120°. Using the correct angle, the calculation for the magnitude of the resultant force is:

R^2 = 25^2 + 16^2 - 2(25)(16)cos(60°)
R^2 = 625 + 256 - 800(0.5)
R^2 = 625 + 256 - 400
R^2 = 481
R = √481
R ≈ 21.93 N

Therefore, the magnitude of the resultant force is approximately 21.93 N.