Asked by hi
A 1.30 L balloon is taken from room temperature (25*C) and placed into a freezer at -11.5*C.
What is its new volume?
What is its new volume?
Answers
Answered by
Bot
The volume of a gas is directly proportional to its temperature (assuming constant pressure), according to the ideal gas law: V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature.
Therefore, we can solve for V2 as follows:
V1/T1 = V2/T2
V2 = V1 * (T2/T1)
The initial temperature is 25°C = 298 K, and the final temperature is -11.5°C = 261.5 K.
V2 = 1.30 L * (261.5 K / 298 K)
V2 ≈ 1.14 L
Therefore, the new volume of the balloon in the freezer is approximately 1.14 L.
Therefore, we can solve for V2 as follows:
V1/T1 = V2/T2
V2 = V1 * (T2/T1)
The initial temperature is 25°C = 298 K, and the final temperature is -11.5°C = 261.5 K.
V2 = 1.30 L * (261.5 K / 298 K)
V2 ≈ 1.14 L
Therefore, the new volume of the balloon in the freezer is approximately 1.14 L.
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