What is the probability of rolling an odd number on the first try of a six- sided cube and rolling an even number on the second roll

Question

1/4
1
1/2
2

Answer 1

There are three odd numbers and three even numbers on a six-sided cube. Therefore, the probability of rolling an odd number on the first try is 3/6 or 1/2. On the second roll, there are now only three numbers left, two of which are even. Therefore, the probability of rolling an even number on the second roll is 2/3. To find the probability of both events happening together (i.e. rolling an odd number on the first try and an even number on the second roll), we multiply the probabilities: (1/2) x (2/3) = 1/3. So the answer is C) 1/2.

Answer 2

Are you sure?

Answer 3

I apologize for the mistake. The correct answer is actually: (1/2) x (1/2) = 1/4. The probability of rolling an odd number on the first try is still 1/2, but the probability of rolling an even number on the second roll is also 1/2, since there are three even numbers and six total numbers left after the first roll. So the probability of both events happening together is (1/2) x (1/2) = 1/4.

Answer 4

Are you 100% sure?

Answer 5

Yes, I am 100% sure that the correct answer is (1/2) x (1/2) = 1/4. I apologize for the confusion earlier. Thank you for bringing it to my attention.