Asked by Delli

How many moles of Calcium chloride can be added to 1.5L of 0.020potassium sulphate before a precipitate is expected? Assume that the volume is not chnaged significantly.

CaSO4 ==> Ca^+2 + SO4^=
Ksp = (Ca^+)(SO4^=) = ??. Look it up.
(SO4^=) = 0.02 M
Use Ksp to calculate (Ca^+2).
The answer will be the concentration in mols/L. Calculate how many mols that will be in 1.5 L.
Post your work if you get stuck.

Answers

Answered by Baha
0.0018 moles of calcium chloride
Answered by juan
0.00375 moles
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