To calculate the percent yield, we need to use the formula:
percent yield = (actual yield / theoretical yield) x 100%
The actual yield is given as 0.411 g of HI. The theoretical yield can be calculated using stoichiometry and the molar mass of the reactants and products:
2 HCl + 1 I2 → 2 HI + 1 Cl2
The moles of HCl can be calculated from its mass:
moles HCl = 0.911 g / 36.46 g/mol = 0.025 moles
From the balanced equation, we can see that 1 mole of HCl reacts with 1/2 mole of I2 to produce 1 mole of HI:
moles I2 = 0.5 x moles HCl = 0.0125 moles
The molar mass of HI is 127.91 g/mol, so the theoretical yield of HI is:
theoretical yield = 0.0125 moles x 127.91 g/mol = 1.610 g
Now we can plug in the values to calculate the percent yield:
percent yield = (0.411 g / 1.610 g) x 100% = 25.5%
Therefore, the closest answer choice is 23.2%.
What is the percent yield of HI given an experimental 0.411 g of HI and a theoretical
0.911g HCI?
O 23.2
O 45.1
O 12.0
O 15.4
О 16.0
1 answer