What is the the percent by volume %(m/v), of a NaCI solution prepared by mixing 50.0 g NaCI with 48.0gram of pure water to create an experimentally determined final measured solutio of

Question

100mL

Answer 1

First, we need to calculate the volume of the 50.0 g NaCI solution assuming it has the same density as water (1 g/mL):

mass = volume x density
volume = mass/density
volume = 50.0 g / 1 g/mL
volume = 50.0 mL

Now, we can calculate the % (m/v) of the NaCI solution:

% (m/v) = (mass of solute/volume of solution) x 100%
% (m/v) = (50.0 g / 100.0 mL) x 100%
% (m/v) = 50.0%

Therefore, the percent by volume %(m/v) of the NaCI solution is 50.0%.