Question

The specific heat (heat capacity) of toretel is found to be 4.9 (cal/g * °C). What is the amount of energy transferred in in Kcal if 3.00g toretel changes in temperature from 102.
°C to 130. °C?
O 5.29 Kcal
O 814 Kcal
O 2,280 Kcal
O 0.42 Kcal
O 2.28 Kcal
O 490 Kcal

Answer 1

First, we need to calculate the change in temperature:

ΔT = 130 °C - 102 °C = 28 °C

Then, we can use the formula:

q = m * c * ΔT

where q is the amount of energy transferred (in calories), m is the mass of the substance (in grams), c is the specific heat (in cal/g * °C), and ΔT is the change in temperature (in °C).

Plugging in the values:

q = 3.00 g * 4.9 (cal/g * °C) * 28 °C

q = 411.6 cal

Finally, to convert calories to kilocalories, we divide by 1000:

q = 0.4116 kcal

Rounding to two significant figures, the answer is:

0.42 Kcal