Question
A sample of 02 gas occupies a volume of 1.20L at a pressure 735 mm Hg and a temperature of 225°C. What is the final volume if the temperature is increased to 685°C. and the pressure does not change? HINT: Convert temperature first
a.1.30 L O2
b. 4.30 L 02
c. 8.60 L O2
d. 2.30 L Oz
above
e. none of the
a.1.30 L O2
b. 4.30 L 02
c. 8.60 L O2
d. 2.30 L Oz
above
e. none of the
Answers
above
First, we need to convert the temperature from Celsius to Kelvin:
T1 = 225°C + 273.15 = 498.15 K
T2 = 685°C + 273.15 = 958.15 K
Now we can use the combined gas law to solve for V2:
(P1V1/T1) = (P2V2/T2)
Plugging in the given values:
(735 mmHg)(1.20 L)/(498.15 K) = (735 mmHg)(V2)/(958.15 K)
Simplifying:
V2 = (735 mmHg)(1.20 L)(958.15 K) / (735 mmHg)(498.15 K)
V2 = 2.33 L
Therefore, the final volume is 2.33 L of O2 (option d).
First, we need to convert the temperature from Celsius to Kelvin:
T1 = 225°C + 273.15 = 498.15 K
T2 = 685°C + 273.15 = 958.15 K
Now we can use the combined gas law to solve for V2:
(P1V1/T1) = (P2V2/T2)
Plugging in the given values:
(735 mmHg)(1.20 L)/(498.15 K) = (735 mmHg)(V2)/(958.15 K)
Simplifying:
V2 = (735 mmHg)(1.20 L)(958.15 K) / (735 mmHg)(498.15 K)
V2 = 2.33 L
Therefore, the final volume is 2.33 L of O2 (option d).
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