Car A went 60 km in 5/6 of an hour whilst a Car B went 54 in 2/3 of an hour. And which car was faster? How many times faster?

Answer 1

To compare the speeds of the two cars, we need to find their respective speeds.

Car A: speed = distance ÷ time = 60 km ÷ (5/6) hour = 72 km/hour

Car B: speed = distance ÷ time = 54 km ÷ (2/3) hour = 81 km/hour

Therefore, Car B was faster than Car A. Car B was (81/72) = 1.125 times faster than Car A (or 12.5% faster).

Answer 2

For this inequality, draw a number line and show all point that satisfy it.

1.1<t<=1 3/4

Answer 3

To solve the inequality 1.1 < t ≤ 1 3/4, we need to find all values of t that are greater than 1.1 but less than or equal to 1 3/4.

1.1 < t means that t can be any number greater than 1.1, but not including 1.1.

t ≤ 1 3/4 means that t can be any number less than or equal to 1 3/4.

Putting these two together, we get:

1.1 < t ≤ 1 3/4

We can graph this inequality on a number line as follows:

<pre>
-------------------|---------------------------|------------------------|--------------------
1.1 1 1 3/4
</pre>

The shaded area between 1.1 and 1 3/4, including 1 3/4, represents all the values of t that satisfy the inequality.