Asked by jaz
The terminal side of an angle in standard position goes through the poin (-2,5). Find the values of the 6 trig function
sin
cos
tan
csc
sec
cot
sin
cos
tan
csc
sec
cot
Answers
Answered by
Reiny
did you make a diagram?
you would have a right-angled triangle in the second quadrant with x=-2 and r=5
so
x^2 + y^2 = r^2
4 + y^2 = 25
y = ± √21
but we are in quadrant II, so y = +√21
now, knowing the trig rations in terms of x,y, and r, your question is easy
e.g. tan(angle) = y/x = - √21/2
sec(angle) = r/x = - 5/2
you do the rest.
you would have a right-angled triangle in the second quadrant with x=-2 and r=5
so
x^2 + y^2 = r^2
4 + y^2 = 25
y = ± √21
but we are in quadrant II, so y = +√21
now, knowing the trig rations in terms of x,y, and r, your question is easy
e.g. tan(angle) = y/x = - √21/2
sec(angle) = r/x = - 5/2
you do the rest.
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