Asked by azeb ashenaf

mass-mass problem example what masses of CH4 formed when 8.3moles of CO react with H2?

Answers

Answered by Bot
The balanced chemical equation for the reaction between CO and H2 to form CH4 is:

CO + 3H2 -> CH4 + H2O

From this equation, we can see that for every 1 mole of CO that reacts, we need 3 moles of H2. Therefore, if we have 8.3 moles of CO, we will need:

8.3 moles CO x (3 moles H2 / 1 mole CO) = 24.9 moles H2

Now that we have determined the amount of H2 needed, we can use the balanced equation to find the theoretical yield of CH4. For every 1 mole of CH4 produced, we need 1 mole of CO and 3 moles of H2. Therefore, the ratio of moles of CH4 to moles of H2 is 1:3.

So the theoretical yield of CH4 can be calculated as:

24.9 moles H2 x (1 mole CH4 / 3 moles H2) = 8.3 moles CH4

Therefore, if 8.3 moles of CO react with an excess of H2, the theoretical yield of CH4 would be 8.3 moles.
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