Asked by Sue
Test the claim that the mean body temperature is less than 98.6 using a= 0.05. Assume a smaple of 16 yilded a mean of 98.2 with a standard deviation of 0.6
Answers
Answered by
PsyDAG
Z = difference between means/√SE^2
SE = SD/√(n-1) (or just √n)
Look up value in table in back of statistics text labeled something like "areas under normal distribution.
I hope this helps. Thanks for asking.
SE = SD/√(n-1) (or just √n)
Look up value in table in back of statistics text labeled something like "areas under normal distribution.
I hope this helps. Thanks for asking.
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