Asked by Susan Udensi

Find the area of a square whose perimeter is 40cm
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How many numbers between 9 and 49 are divisible by 6?
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If m=4 and n = 3 what is the value of the product of (m+n) and (m_n)?
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Formula of volume of a cube?
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Find the volume of a cube with sides 4cm
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A rectangular water tank 6m by 4m by 5m is half full of water. What volume of water is in the tank?
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How many faces has a cube of sugar
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The proportion of boys to girls in a class is 1:4. If there are 45 pupils, how many girls are there?
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Prime numbers between 0 and 7
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What is the value of angle marked z in a right angle triangle if the other Angeles are 90° and 45°?
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Find the area of a T shaped shape with 2cm, 2cm the up part and 5cm, 5cm, up part 7cm, 7cm añd 2cm the down part
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What is the proportion of the air needed for burning
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the proportion of the air needed for burning is ............... Of the atmosphere
Answered by Bot
If the perimeter of a square is 40cm, then each side length is 10cm (since all sides of a square are equal).

To find the area of the square, we use the formula:

Area = Side length x Side length

Plugging in our value for the side length:

Area = 10cm x 10cm

Area = 100cm²

Therefore, the area of the square is 100cm².
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The first multiple of 6 that is greater than or equal to 9 is 12. The last multiple of 6 that is less than or equal to 49 is 48. We need to count the number of multiples of 6 that are between 12 and 48 (inclusive).

To do this, we can list the multiples of 6 in this range and count them:

12, 18, 24, 30, 36, 42, 48

There are 7 numbers in this list, so there are 7 numbers between 9 and 49 that are divisible by 6.
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Assuming that the underscore between m and n is meant to indicate multiplication, we can solve the problem as follows:

(m+n) = (4+3) = 7

(m_n) = (4_3) = (4 x 3) = 12

The product of (m+n) and (m_n) is obtained by multiplying these two values:

(m+n) x (m_n) = 7 x 12 = 84

Therefore, the value of the product of (m+n) and (m_n) is 84.
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The formula for the volume (V) of a cube is:

V = s^3

where s is the length of one side of the cube.

In other words, to find the volume of a cube, you simply need to cube the length of one of its sides.
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Using the formula for the volume of a cube:

V = s^3

where s is the length of one side of the cube.

If the length of each side of the cube is 4cm, then we can substitute s = 4cm into the formula:

V = 4cm^3

Simplifying:

V = 64cm³

Therefore, the volume of the cube is 64 cubic centimeters (cm³).
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The volume of the rectangular water tank is:

V = l × w × h = 6m × 4m × 5m = 120 cubic meters (m³)

Since the tank is half full of water, the volume of water in the tank will be half of the volume of the tank:

V_water = 1/2 × 120 m³ = 60 cubic meters (m³)

Therefore, the volume of water in the tank is 60 cubic meters (m³).
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A cube of sugar has 6 faces.

A cube is a three-dimensional shape that has 6 faces, each of which is a square. Since a cube of sugar is a cube-shaped object, it also has 6 faces, which are all identical squares.
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If the ratio of boys to girls in a class is 1:4, this means for every one boy, there are four girls.

Let's call the number of boys "x". Then, the number of girls is 4x, since there are four times as many girls as boys.

We know that the total number of pupils in the class is 45. So:

x + 4x = 45

5x = 45

x = 9

This tells us there are 9 boys in the class. To find the number of girls, we can multiply the number of boys by 4:

4x = 4(9) = 36

So there are 36 girls in the class.
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The prime numbers between 0 and 7 are 2, 3, 5, and 7.

- 2 is the only even prime number and it is the smallest prime number.
- 3 is the next prime number after 2 and it is the only prime number that is one more than a multiple of 3.
- 5 is the next prime number after 3 and it is the only prime number that is one less than a multiple of 6.
- 7 is the next prime number after 5 and it is the only prime number that is two less than a multiple of 6.

Therefore, the prime numbers between 0 and 7 are 2, 3, 5, and 7.
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In a right triangle (one angle measuring 90°), the sum of the other two angles must be 90°.

If one of the angles in the right triangle is 45°, then the other angle must be:

90° - 45° = 45°

So we have two angles in the triangle: 45° and 90°.

The sum of all three angles in any triangle is always 180°.

Therefore:

180° = 45° + 90° + z

Simplifying:

45° + z = 90°

z = 90° - 45°

z = 45°

So the third angle z in the right triangle is 45°.
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To find the area of the T-shaped shape, we need to split it into two parts - the two rectangles and subtract the area of the smaller rectangle from the larger one:

Step 1: Find the area of the larger rectangle

The larger rectangle has dimensions of 7cm (height) and 4cm (width) + 2cm (width) = 6cm (total width).

Area of larger rectangle = height × width = 7cm × 6cm = 42cm²

Step 2: Find the area of the smaller rectangle

The smaller rectangle has dimensions of 2cm (height) and 2cm (width).

Area of smaller rectangle = height × width = 2cm × 2cm = 4cm²

Step 3: Find the area of the T-shaped shape

The area of the T-shaped shape is the area of the larger rectangle minus the area of the smaller rectangle:

Area of T-shaped shape = 42cm² - 4cm²

Area of T-shaped shape = 38cm²

Therefore, the area of the T-shaped shape is 38 square centimeters (cm²).
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For burning (combustion) to occur, a fuel source needs to react with oxygen in the air. The ideal proportion of air needed for burning depends on the type of fuel being burned.

One common type of fuel is hydrocarbons, which include substances like gasoline, diesel fuel, and natural gas. The ideal proportion of air needed for burning hydrocarbons is called the stoichiometric ratio, which is the exact ratio of air to fuel needed for complete combustion.

For example, the stoichiometric ratio for burning gasoline is approximately 14.7 parts air to 1 part gasoline. This means that for every 1 unit of gasoline (by mass or volume), approximately 14.7 units of air (by mass or volume) are needed for complete combustion.

In practice, however, it is often difficult to achieve the exact stoichiometric ratio for burning. Engines and other combustion devices may adjust the air/fuel ratio to optimize performance, which can result in more or less air being used than the stoichiometric ratio would suggest.
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The proportion of air needed for burning (combustion) depends on the type of fuel being burned and the stoichiometric ratio.

However, regardless of the fuel type and stoichiometric ratio, the air needed for burning is always a fraction of the atmosphere.

The Earth's atmosphere is composed of several gases, including nitrogen (78.08%), oxygen (20.95%), argon (0.93%), and trace amounts of other gases like carbon dioxide and neon. When a fuel is burned, only the oxygen in the air is consumed in the combustion process.

Therefore, the proportion of air needed for burning is a fraction of the atmosphere's oxygen content, which is approximately 20.95%. This means that, for example, if the stoichiometric ratio for burning gasoline is 14.7 parts air to 1 part gasoline, then only a fraction of the 20.95% of oxygen in the air is consumed during the combustion process.