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                a bag contains 5 green marbles, 8 red marbles, 11 yellow marbles, 7 brown marbles, 12 blue marbles, you pick a marble, replace it, and pick another one, what is P(red, then blue)
            
            
        Answers
                    Answered by
            Bot
            
    The probability of picking a red marble on the first attempt is 8/43, as there are 8 red marbles out of 43 total marbles in the bag. After replacing the red marble back in the bag, the probability of picking a blue marble on the second attempt is 12/43, as there are 12 blue marbles out of 43 total marbles in the bag.
Therefore, the probability of picking a red marble and then a blue marble is:
P(red, then blue) = P(red) x P(blue | red)
P(red, then blue) = (8/43) x (12/43)
P(red, then blue) = 96/1849
Therefore, the probability of picking a red marble and then a blue marble is 96/1849 or approximately 0.052.
    
Therefore, the probability of picking a red marble and then a blue marble is:
P(red, then blue) = P(red) x P(blue | red)
P(red, then blue) = (8/43) x (12/43)
P(red, then blue) = 96/1849
Therefore, the probability of picking a red marble and then a blue marble is 96/1849 or approximately 0.052.
                    Answered by
            Bot
            
    There are two vowels in the set: E and I. Therefore, the probability of getting a vowel on the first spin is 2/7.
After replacing the spinner back in the same condition, the probability of getting Q on the second spin is 1/7, as there is only one Q in the set of possible letters.
Thus, the probability of getting a vowel on the first spin and Q on the second spin is:
P(vowel, then Q) = P(vowel) x P(Q | vowel)
P(vowel, then Q) = (2/7) x (1/7)
P(vowel, then Q) = 2/49
Therefore, the probability of getting a vowel on the first spin and Q on the second spin is 2/49 or approximately 0.041.
    
After replacing the spinner back in the same condition, the probability of getting Q on the second spin is 1/7, as there is only one Q in the set of possible letters.
Thus, the probability of getting a vowel on the first spin and Q on the second spin is:
P(vowel, then Q) = P(vowel) x P(Q | vowel)
P(vowel, then Q) = (2/7) x (1/7)
P(vowel, then Q) = 2/49
Therefore, the probability of getting a vowel on the first spin and Q on the second spin is 2/49 or approximately 0.041.
                    Answered by
            Bot
            
    The answer is not one of the choices given. 
As previously calculated, the probability of getting a vowel on the first spin and Q on the second spin is:
P(vowel, then Q) = P(vowel) x P(Q | vowel)
P(vowel, then Q) = (2/7) x (1/7)
P(vowel, then Q) = 2/49
Therefore, the probability of getting a vowel on the first spin and Q on the second spin is 2/49.
    
As previously calculated, the probability of getting a vowel on the first spin and Q on the second spin is:
P(vowel, then Q) = P(vowel) x P(Q | vowel)
P(vowel, then Q) = (2/7) x (1/7)
P(vowel, then Q) = 2/49
Therefore, the probability of getting a vowel on the first spin and Q on the second spin is 2/49.
                    Answered by
            Bot
            
    2/49 cannot be simplified any further. Therefore, the simplified form of 2/49 is just 2/49.
    
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