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the length of the vector c= (2,-3,1) is
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The length of a vector c = (a,b,c) is given by:
|c| = √(a^2 + b^2 + c^2)
Therefore, the length of the vector c = (2,-3,1) is:
|c| = √(2^2 + (-3)^2 + 1^2) = √(4 + 9 + 1) = √14
So, the length of the vector c is √14.
|c| = √(a^2 + b^2 + c^2)
Therefore, the length of the vector c = (2,-3,1) is:
|c| = √(2^2 + (-3)^2 + 1^2) = √(4 + 9 + 1) = √14
So, the length of the vector c is √14.