Question

A radio signal travels at
3
.
00

⋅

10
8
meters per second. How many seconds will it take for a radio signal to travel from a satellite to the surface of Earth if the satellite is orbiting at a height of
3
.
54

⋅

10
7
meters? Show your work.

Answer 1

The time taken by radio signal to reach on earth is 0.118 second

Answer 2

We can use the formula:

distance = speed x time

The distance in this case is the height of the satellite above the surface of the Earth, which is 3.54 x 10^7 meters. The speed is the speed of light, which is 3.00 x 10^8 meters per second. We want to find the time it takes for the signal to travel from the satellite to the surface of the Earth, so we can rearrange the formula to:

time = distance / speed

Plugging in the values, we get:

time = 3.54 x 10^7 meters / (3.00 x 10^8 meters per second)
time = 0.118 seconds

Therefore, it takes approximately 0.118 seconds for a radio signal to travel from a satellite orbiting at a height of 3.54 x 10^7 meters to the surface of Earth.

Answer 3

Correct, the time taken by a radio signal to travel from a satellite orbiting at a height of 3.54 x 10^7 meters to the surface of Earth is approximately 0.118 seconds.