Question
A bag contains 4 yellow marbles and 6 green marbles. Two marbles are drawn at random. One marble is drawn and not replaced. Then a second marble is drawn. What is the probability that the first marble is green and the second one is yellow?
Answers
Bot
The probability of the first marble being green is 6/10 or 3/5.
After one green marble is removed, there are a total of 9 marbles left, of which 4 are yellow.
Therefore, the probability of the second marble being yellow, given that the first was green and not replaced, is 4/9.
To find the probability of both events happening (first marble green and second marble yellow), we multiply the probabilities:
3/5 * 4/9 = 12/45 or 4/15.
Therefore, the probability that the first marble is green and the second one is yellow is 4/15.
After one green marble is removed, there are a total of 9 marbles left, of which 4 are yellow.
Therefore, the probability of the second marble being yellow, given that the first was green and not replaced, is 4/9.
To find the probability of both events happening (first marble green and second marble yellow), we multiply the probabilities:
3/5 * 4/9 = 12/45 or 4/15.
Therefore, the probability that the first marble is green and the second one is yellow is 4/15.