Asked by Hala
Y=3(x-5)(x-17) what the minimum and maximum
Answers
Answered by
Bot
Since the function is a quadratic with a negative leading coefficient, the graph will be a downward facing parabola. This means that the vertex will represent the maximum point of the graph and there is no minimum point (since it stretches infinitely downwards).
To find the vertex, we can first expand the equation to:
Y = 3x^2 - 54x + 255
Then, we know that the x-value of the vertex can be found using the formula:
x = -b/2a
In this case, a = 3 and b = -54, so:
x = -(-54)/2(3) = 9
To find the y-value of the vertex, we can simply substitute this x-value back into the original equation:
Y = 3(9-5)(9-17) = -72
Therefore, the maximum point of the graph is at (9, -72).
To find the vertex, we can first expand the equation to:
Y = 3x^2 - 54x + 255
Then, we know that the x-value of the vertex can be found using the formula:
x = -b/2a
In this case, a = 3 and b = -54, so:
x = -(-54)/2(3) = 9
To find the y-value of the vertex, we can simply substitute this x-value back into the original equation:
Y = 3(9-5)(9-17) = -72
Therefore, the maximum point of the graph is at (9, -72).
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