Y=3(x-5)(x-17) what the zeros and Axis of symmetry

Answer 1

First, we need to simplify the equation by multiplying the two binomials:

Y=3(x-5)(x-17)

Y=3(x²-22x+85)

Y=3x²-66x+255

The axis of symmetry is given by the formula:

x= -b/2a

where a = 3 and b = -66.

x= -(-66)/2(3)

x= 11

So, the axis of symmetry is x = 11.

To find the zeros, we set Y equal to zero:

0=3x²-66x+255

We can simplify this equation by dividing everything by 3:

0=x²-22x+85

Now we need to factor the quadratic equation:

0=(x-5)(x-17)

So the zeros are x=5 and x=17.

Therefore, the zeros are x = 5 and x = 17, and the axis of symmetry is x = 11.