To find the mean of the absolute differences, we first need to find the mean of the given numbers:
(141+330+292+198+263+224+149+121+223+125+126+48+111+327+238) / 15 = 204.6
Next, we find the absolute difference between each number and the mean and add them up:
|141-204.6| + |330-204.6| + |292-204.6| + |198-204.6| + |263-204.6| + |224-204.6| + |149-204.6| + |121-204.6| + |223-204.6| + |125-204.6| + |126-204.6| + |48-204.6| + |111-204.6| + |327-204.6| + |238-204.6|
= 63.6 + 125.4 + 87.4 + 6.6 + 58.4 + 19.4 + 55.6 + 83.6 + 18.4 + 79.6 + 78.6 + 156.6 + 93.6 + 122.4 + 122.4 = 1151.2
Finally, we divide the sum by the number of numbers (15) to find the mean of the absolute differences:
1151.2 / 15 = 76.747.
Therefore, the mean of the absolute differences between each number and the mean of these numbers is approximately 76.747.
Find the mean of the absolute differences between each number and the mean of these numbers 141, 330, 292, 198, 263, 224, 149, 121, 223, 125, 126, 48, 111, 327, 238
3 answers
76.747 no the nearest 100
The nearest 100 to 76.747 is 100. Therefore, the mean of the absolute differences between each number and the mean of these numbers to the nearest 100 is 100.