is it possible for two boxes to have the same volume, but different surface area's? give examples to prove your point.
please help, cannot think of anything. THANKS =]
8 answers
First tell me what are surfaces.
Do you mean the base?
wellit it is possible with B=0 and H=0
b is base and h is height. But i don't think having a 0 0 cube is possible! :)
b is base and h is height. But i don't think having a 0 0 cube is possible! :)
Sure
Example: B-8 H-3 and B-6 H-4
Example: B-8 H-3 and B-6 H-4
Sorry, I typed thaT incorrectly...
H-8 D-1 W-1 and H-6 D-4 W-1
H-8 D-1 W-1 and H-6 D-4 W-1
no for the first one the surface area would be 17? Surface area= BH+BW+WH
sure it is.
e.g.
consider a volume of 60 cm^3
box #1: 3x4x5
vol = 60
Surface area = 2(3x4 + 3x5 + 4x5) = 94
box #2: 6x2x5
volume = 60
Surface area = 2(6x2 + 6x5 + 4x5) = 124
e.g.
consider a volume of 60 cm^3
box #1: 3x4x5
vol = 60
Surface area = 2(3x4 + 3x5 + 4x5) = 94
box #2: 6x2x5
volume = 60
Surface area = 2(6x2 + 6x5 + 4x5) = 124
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