Asked by Carmin
Please Simplify
(2^-1∙7^-4)^-2
(2^-1∙7^-4)^-2
Answers
Answered by
Cody
4-2.89+16
answer= 17.11
answer= 17.11
Answered by
Reiny
= 2^2 * 7^8 or 23059204
Answered by
jose
first 2^-1 = -3
then 7^-4=-5
-3x-5=15
15^-2=15 so your answer is 15
i suggest you use a scientific calculator.
then 7^-4=-5
-3x-5=15
15^-2=15 so your answer is 15
i suggest you use a scientific calculator.
Answered by
Cody
well we all got different answers but i think jose is right ;)
Answered by
jose
thanks =D.
Answered by
Reiny
(2^-1∙7^-4)^-2
= [(1/2)(1/7^4)^-2
= (1/4802)^-2
= (4802/1)^2
= 23059204
or
(2^-1∙7^-4)^-2 , using the rule (a^x)^y = a^xy
= [(2^2)(7^8)]
= 4(5764801)
= 23059204
ho, hum !
= [(1/2)(1/7^4)^-2
= (1/4802)^-2
= (4802/1)^2
= 23059204
or
(2^-1∙7^-4)^-2 , using the rule (a^x)^y = a^xy
= [(2^2)(7^8)]
= 4(5764801)
= 23059204
ho, hum !
Answered by
Cody
how do you square 2 and get 1/2?
Answered by
Reiny
Cody, please learn the rules of exponents
2^-1 = (1/2)^+1 = 1/2
<b>a<sup>-n</sup> = 1/a<sup>n</sup></b>
2^-1 = (1/2)^+1 = 1/2
<b>a<sup>-n</sup> = 1/a<sup>n</sup></b>
Answered by
Cody
ohhhh sorry about that. i didn't see the negative, i thought it was positive. :(
Answered by
Carmin
So here are the choices
2^2*7^8
2^5 * 7^5
1/both of them
2^2*7^8
2^5 * 7^5
1/both of them
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