Asked by Beth
Help please! I think this is the way to solve this problem, but am not sure. Any help is most appreciated. Thanks!
Simplify
(p^4 + m p^2m)^-4/(p^-4)^-m
Simplify
(p^4 + m p^2m)^-4/(p^-4)^-m
Answers
Answered by
Reiny
I see this as
1/[(p<sup>4</sup> + mp<sup>2m</sup>)<sup>4</sup>(p<sup>4</sup>)
anything else done, such as expanding that binomial, would not considered "simplifying"
You said you think there is a way to 'solve' this,
what exactly were you thinking?
1/[(p<sup>4</sup> + mp<sup>2m</sup>)<sup>4</sup>(p<sup>4</sup>)
anything else done, such as expanding that binomial, would not considered "simplifying"
You said you think there is a way to 'solve' this,
what exactly were you thinking?
Answered by
Carmin
either adding or multiplying exponents
The possible answers are as follows
p^-16m + 16
p^-8m – 4
p^-11m – 4
p^-3m + 16
The possible answers are as follows
p^-16m + 16
p^-8m – 4
p^-11m – 4
p^-3m + 16
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