Let the first term be "a" and the common ratio be "r". Then we have:
Second term: ar = 1
Fifth term: ar^4 = 1/8
Dividing the two equations, we get:
(ar^4) / (ar) = (1/8) / 1
Simplifying and solving for "r", we get:
r^3 = 1/8
r = 1/2
Substituting this back into the equation for the second term, we get:
ar = 1
a(1/2) = 1
a = 2
Therefore, the first term is 2.
The second and fifth term of a geometric progression are 1 and⅛ respectively find the first term
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