Question

You roll a number cube twice find P (even then not 2) to write the probability as a fraction in simplest form

Answer 1

A number cube is rolled 450 times the number 3 comes up 67 times A. what is at theoretical probability Of rolling a 3 write your answer as a fraction in simplest form B. what is the experimental probability of rolling up 3 write your answer as a fraction in simplest form

Answer 2

You mix the letters mathematical thoroughly without looking you draw one letter find a probability PA Write the probability as A. fraction in simplest form B. a decimal C. A percent

Answer 3

There are six possible outcomes when rolling a number cube twice: (1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6).

To find P(even then not 2), we need to first determine the number of outcomes that satisfy both conditions.

Condition 1: Even number on first roll.
This can be achieved with the following outcomes: (2,1), (2,3), (2,5), (4,1), (4,3), (4,5), (6,1), (6,3), (6,5). There are 9 such outcomes.

Condition 2: Not 2 on second roll.
This can be achieved with the following outcomes: (1,1), (1,3), (1,4), (1,5), (1,6), (2,1), (2,3), (2,4), (2,5), (2,6), (3,1), (3,3), (3,4), (3,5), (3,6), (4,1), (4,3), (4,4), (4,5), (4,6), (5,1), (5,3), (5,4), (5,5), (5,6), (6,1), (6,3), (6,4), (6,5), (6,6). There are 28 such outcomes.

To find the number of outcomes that satisfy both conditions, we need to find the intersection of the two sets of outcomes. We see that only the outcomes (2,1) and (2,5) satisfy both conditions. Therefore, there are 2 outcomes that satisfy both conditions.

To find the probability of rolling an even number then not 2, we need to divide the number of outcomes that satisfy both conditions by the total number of possible outcomes.
P(even then not 2) = 2/36 = 1/18.

Therefore, the probability of rolling an even number then not 2 is 1/18.

Answer 4

A. The theoretical probability of rolling a 3 on a number cube is 1/6. This is because there is only one outcome that results in rolling a 3, and there are six possible outcomes in total.

B. The experimental probability of rolling a 3 is calculated by dividing the number of times a 3 comes up by the total number of rolls. In this case, the experimental probability is:

67/450

This can be simplified by dividing both the numerator and denominator by 5:

13/90

Therefore, the experimental probability of rolling a 3 is 13/90.

Answer 5

To begin with, we need to know how many letters are in the word "mathematical" so we can determine the total number of possible outcomes. There are 11 letters in "mathematical".

A. To find the probability of drawing a specific letter, we need to determine how many of that letter there are in the word "mathematical". Then, we can divide that number by the total number of letters in the word. For example, let's find the probability of drawing the letter "a". There are 2 "a"s in "mathematical". Therefore, the probability of drawing an "a" is:

2/11

This is the probability as a fraction in simplest form.

B. To find the probability as a decimal, we simply divide the numerator by the denominator:

2 ÷ 11 = 0.1818...

The decimal is 0.18, rounded to two decimal places.

C. To find the probability as a percentage, we multiply the fraction by 100:

2/11 × 100 = 18.18...

The percentage is 18.18%, rounded to two decimal places.