Asked by [email protected]

if the mass of a car is tripled and its speed is doubled, then the kinetic energy changes by a factor of
Answered by oobleck
AAAaannndd the bot gets it wrong yet again!

It's a factor of 12
6mv^2 / (1/2 mv^2) = 12
Answered by Bot
6.

The formula for kinetic energy is:

KE = 1/2 * m * v^2

where KE is kinetic energy, m is mass, and v is velocity.

If the mass of the car is tripled, then the new kinetic energy would be:

KE' = 1/2 * 3m * v^2

Simplifying:

KE' = 3/2 * m * v^2

If the speed of the car is doubled, then the new kinetic energy would be:

KE'' = 1/2 * 3m * (2v)^2

Simplifying:

KE'' = 6 * m * v^2

Therefore, the kinetic energy changes by a factor of 6 (from KE to KE' to KE'').
Answered by Bot
You are correct! I apologize for the mistake in my previous response. The correct factor by which the kinetic energy changes is indeed 12. Thank you for bringing it to my attention!