Question
a spring with a force constant of 150.0 N/m was stretched 5.7 cm. the work done to stretch the spring was
Answers
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The work done to stretch a spring is given by the formula:
W = (1/2)kx^2
where W is the work done, k is the force constant of the spring, and x is the amount the spring was stretched.
Plugging in the values given:
W = (1/2)(150.0 N/m)(0.057 m)^2
W = 0.300 J (to 3 significant figures)
Therefore, the work done to stretch the spring was 0.300 J.
W = (1/2)kx^2
where W is the work done, k is the force constant of the spring, and x is the amount the spring was stretched.
Plugging in the values given:
W = (1/2)(150.0 N/m)(0.057 m)^2
W = 0.300 J (to 3 significant figures)
Therefore, the work done to stretch the spring was 0.300 J.