A bag contains tiles with the letters P-R-O-B-A-B-I-L-I-T-Y. Tyler chooses a tile without looking and doesn't replace it. He chooses a second tile without looking. What is the probability that he will choose the letter I both times?

Question

1/55
2/55
2/121
3/121

Answer 1

The probability of choosing the letter I on the first draw is 2/12 (since there are two I's out of a total of 12 letters). Since Tyler does not replace the first tile, there is now one less tile in the bag and one less I, so the probability of choosing another I on the second draw is now 1/11. Therefore, the probability of choosing I twice in a row is:

(2/12) x (1/11) = 2/132

Simplifying, we get:

2/132 = 1/66

Therefore, the answer is not given in the options.

Answer 2

A sandwich shop offers the following toppings. How many two-topping sandwiches can you make?
- lettuce
- tomato
- Bacon
- Cheese
- Mustard
(1 point)

8
10
12
20

Answer 3

To find the number of two-topping sandwiches that can be made, we need to use the combination formula:

nCx = n! / (x! * (n-x)!)

where n is the total number of toppings and x is the number of toppings we want to choose (in this case, 2).

Plugging in the numbers, we get:

5C2 = 5! / (2! * (5-2)!)
= 5! / (2! * 3!)
= (5 * 4 * 3 * 2 * 1) / [(2 * 1) * (3 * 2 * 1)]
= 10

Therefore, there are 10 two-topping sandwiches that can be made.

Answer: 10.