First, we need to find the proportion of white and red balls in each bowl based on the selections made by Clark.
For Bowl A:
- Proportion of white balls = 45/100 = 0.45
- Proportion of red balls = 55/100 = 0.55
For Bowl B:
- Proportion of white balls = 60/100 = 0.6
- Proportion of red balls = 40/100 = 0.4
Next, we need to estimate the expected number of white and red balls in Bowl B based on these proportions, since we know there are 500 balls in Bowl B.
Expected number of white balls in Bowl B = 0.6 x 500 = 300
Expected number of red balls in Bowl B = 0.4 x 500 = 200
The estimated difference in the expected number of white and red balls in Bowl B is:
300 - 200 = 100
Therefore, the estimated difference is 100.
Number of White Balls Selected Number of Red Balls Selected
Bowl A 45 55
Bowl B 60 40
Bowls A and B contain a number of white and red balls. Clark repeatedly selected a ball from both bowls and recorded the results in a table. If there are 500 balls in Bowl B, what is the estimated difference in the expected number of white and red balls in Bowl B?Number of White Balls Selected Number of Red Balls Selected
Bowl A 45 55
Bowl B 60 40
Bowls A and B contain a number of white and red balls. Clark repeatedly selected a ball from both bowls and recorded the results in a table. If there are 500 balls in Bowl B, what is the estimated difference in the expected number of white and red balls in Bowl B?
1 answer